A) 4 g atoms of hydrogen
B) 3.0 g atoms of carbon
C) \[6.02\times {{10}^{23}}\] atoms of hydrogen
D) \[1.81\times {{10}^{23}}\] molecules of \[C{{H}_{4}}\]
Correct Answer: A
Solution :
Key Idea: One mole = molecular mass in gram = 22.4 L at STP \[\text{=}\,\text{6}\text{.0}\text{.23}\times {{10}^{23}}\]atoms/molecules/ions Molecular mass of \[C{{H}_{4}}=12+1\times 4=16\] \[\therefore \] \[16\,g\,\] of \[C{{H}_{4}}=6.023\times {{10}^{23}}\]molecules of \[C{{H}_{4}}\] \[\therefore \] 16 g of \[C{{H}_{4}}\]has 4 g atoms of hydrogen
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