A) 2n
B) n
C) \[\frac{n}{2}\]
D) \[\frac{n}{4}\]
Correct Answer: D
Solution :
In a photocell, the number of emitted electrons is proportional to the intensity of incident light \[\therefore \] \[n\propto I\] and intensity is proportional to the square of distance, that is \[I\propto \frac{1}{{{r}^{2}}}\] \[\therefore \] \[n\propto \frac{1}{{{r}^{2}}}\] \[\Rightarrow \] \[\frac{{{n}_{2}}}{{{n}_{1}}}={{\left( \frac{{{r}_{1}}}{{{r}_{2}}} \right)}^{2}}={{\left( \frac{0.5}{1} \right)}^{2}}=\frac{1}{4}\] \[\Rightarrow \] \[{{n}_{2}}=\frac{{{n}_{1}}}{4}\] Given, \[{{n}_{1}}=n\] \[\therefore \] \[{{n}_{2}}=\frac{n}{4}\]
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