VMMC VMMC Medical Solved Paper-2007

  • question_answer
    Two identical metallic balls, whose temperatures are \[200{}^\circ C\] and \[400{}^\circ C\]respectively, are placed in an enclosure at \[27{}^\circ C\]. The ratio of heat-loss of the balls will be

    A) 1 : 2                                       

    B) 1 : 4                       

    C) \[\frac{{{(473)}^{4}}-{{(300)}^{4}}}{{{(673)}^{3}}-{{(300)}^{4}}}\]

    D) \[\frac{{{(200)}^{4}}-{{(27)}^{4}}}{{{(400)}^{3}}-{{(27)}^{4}}}\]

    Correct Answer: C

    Solution :

    From Stefans-Boltzmanns law the net rate of loss of heat by a black body is \[E=\sigma ({{T}^{4}}-T_{0}^{4})\] T and \[{{T}_{0}}\] being temperatures of body and surrounding,                               Given, \[{{T}_{1}}=200+273=473\,K,\]                 \[{{T}_{0}}=27+273=300\,K,\] \[{{T}_{2}}=400+273=673\,K,\]                 \[\therefore \]  \[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{T_{1}^{4}-T_{0}^{4}}{T_{2}^{4}-T_{0}^{4}}\]                 Hence, \[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{{{(473)}^{4}}{{(300)}^{4}}}{{{(673)}^{4}}-{{(300)}^{4}}}\]


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