A) 1.27\[\overset{0}{\mathop{A}}\,\]
B) 5.08 \[\overset{0}{\mathop{A}}\,\]
C) 2.54\[\overset{0}{\mathop{A}}\,\]
D) 3.59 \[\overset{0}{\mathop{A}}\,\]
Correct Answer: D
Solution :
Interatomic spacing for a fcc lattice \[r={{\left[ {{\left( \frac{a}{2} \right)}^{2}}+{{\left( \frac{a}{2} \right)}^{2}}+{{(0)}^{2}} \right]}^{1/2}}=\frac{a}{\sqrt{2}}\] a being lattice constant. \[\therefore \] \[a=\sqrt{2}r=\sqrt{2}\times 2.54=3.59\overset{\text{o}}{\mathop{\text{A}}}\,\]
You need to login to perform this action.
You will be redirected in
3 sec
