A) 0.5
B) 2
C) \[\frac{5}{3}\]
D) \[\frac{1}{3}\]
Correct Answer: C
Solution :
The time period (T) of vibration magnetometer is \[T=2\pi \sqrt{\frac{I}{MH}}\] where \[I\] is moment of inertia, M the magnetic moment and H the horizontal component of earths field. When likes poles are placed together. \[M={{M}_{1}}+{{M}_{2}}\] When unlike poles are placed together. \[M={{M}_{1}}-{{M}_{2}}\] \[\therefore \] \[\frac{T}{T}=\sqrt{\frac{{{M}_{1}}-{{M}_{2}}}{{{M}_{1}}+{{M}_{2}}}}\] \[\Rightarrow \] \[{{\left( \frac{T}{T} \right)}^{2}}=\frac{{{M}_{1}}-{{M}_{2}}}{{{M}_{1}}+{{M}_{2}}}\] Given, \[\frac{T}{T}=\frac{1}{2}\] \[\therefore \] \[\frac{1}{4}=\frac{{{M}_{1}}-{{M}_{2}}}{{{M}_{1}}+{{M}_{2}}}\] \[\Rightarrow \] \[4{{M}_{1}}-4{{M}_{2}}={{M}_{1}}+{{M}_{2}}\] \[\Rightarrow \] \[3{{M}_{1}}=5{{M}_{2}}\] \[\Rightarrow \] \[\frac{{{M}_{1}}}{{{M}_{2}}}=\frac{5}{3}.\]You need to login to perform this action.
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