VMMC VMMC Medical Solved Paper-2007

  • question_answer
    For coulomb force to be operative the least side of atom will be

    A) \[{{10}^{-12}}m\]            

    B)                        \[{{10}^{-15}}m\]            

    C)                        \[{{10}^{-10}}m\]                            

    D)        \[{{10}^{-8}}m\]

    Correct Answer: B

    Solution :

    Key Idea: Nuclear force is effective within the nuclear diameter. In a nucleus, the positively charged protons and the electrically neutral neutrons exist together in an extremely small space \[(\approx {{10}^{-15}}\,m).\] Naturally there are some forces operating within the nucleus which bind the nucleons together. According to Coulombs law, these forces are \[F=k\frac{{{q}_{1}}{{q}_{2}}}{{{r}^{2}}}.\]They are extremely short range, this means these forces are effective for very short distance only that is within the nuclear diameter \[={{10}^{-15}}\,\text{m}\text{.}\]


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