VMMC VMMC Medical Solved Paper-2007

  • question_answer
    The temperatures of cold and hot junctions of a thermocouple are 0° and T°C respectively. The thermo emf produced is \[E=AT-\frac{1}{2}B{{T}^{2}}\] If A = 16, B = 0.08, the temperature of inversion will be

    A) \[100{}^\circ C\]              

    B)        \[300{}^\circ C\]

    C) \[400{}^\circ C\]                              

    D)        \[500{}^\circ C\]

    Correct Answer: C

    Solution :

    Key Idea: Thermo emf becomes zero at temperature of inversion. As temperature of hot junction rises the thermo emf E increases and becomes maximum and then decreases with rise in temperature and ultimately becomes zero at temperature of inversion. Given,       \[E=AT-\frac{1}{2}B{{T}^{2}}\] When        \[E=0,T={{T}_{i}}\] \[\therefore \]  \[A{{T}_{i}}-\frac{1}{2}BT_{i}^{2}=0\] \[\Rightarrow \]               \[{{T}_{1}}=\frac{2A}{B}\] Putting, \[A=16,B=0.08,\]we get \[{{T}_{i}}=\frac{2\times 16}{0.08}=400{{\,}^{o}}C\] Note: If the temperature of hot junction is further increased beyond the temperature of inversion, the emf is produced in the opposite direction.


You need to login to perform this action.
You will be redirected in 3 sec spinner