VMMC VMMC Medical Solved Paper-2006

  • question_answer
    Ethyl alcohol is heated with conc. \[{{\text{H}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}\text{.}\] The product formed is :

    A)  \[C{{H}_{3}}-\overset{\text{O}}{\mathop{\overset{|\,|}{\mathop{C}}\,}}\,-O{{C}_{2}}{{H}_{5}}\]          

    B)         \[{{C}_{2}}{{H}_{6}}\]                   

    C)         \[{{C}_{2}}{{H}_{4}}\]                   

    D)         \[{{C}_{2}}{{H}_{2}}\]

    Correct Answer: C

    Solution :

     Ethyl alcohol on dehydration with conc. \[{{\text{H}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}\] at \[\text{170}{{\,}^{\text{o}}}\text{C,}\] gives ethylene. \[C{{H}_{3}}C{{H}_{2}}OH\xrightarrow[\text{conc}\text{.}{{\text{H}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}]{\text{170}{{\,}^{\text{o}}}\text{C}}C{{H}_{2}}=\underset{\text{Ethylene}}{\mathop{C{{H}_{2}}}}\,+{{H}_{2}}O\]


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