A) \[30{}^\circ \]
B) \[45{}^\circ \]
C) \[60{}^\circ \]
D) \[15{}^\circ \]
Correct Answer: A
Solution :
The distance of first diffraction minimum from the central principal maximum. \[x=\frac{D\lambda }{d}\] \[\frac{x}{D}=\frac{\lambda }{d}.\] or \[d=\frac{\lambda }{\sin \theta }\] \[\Rightarrow \] \[\sin \theta =\frac{\lambda }{d}=\frac{5000\times {{10}^{-8}}}{1\times {{10}^{-4}}}\] \[\sin \theta =0.5=\sin {{30}^{o}}\] \[\theta ={{30}^{o}}\]
You need to login to perform this action.
You will be redirected in
3 sec
