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VMMC VMMC Medical Solved Paper-2006

  • question_answer
    The magnetic force on a point charge is \[\vec{F}=q\,(\vec{v}\times \vec{B})\]Here, q = electric charge \[\vec{V}\] = velocity of point charge \[\vec{B}\] = magnetic field The dimensions of \[\vec{B}\] is

    A) \[\left[ ML{{T}^{-1}}A \right]\]                  

    B) \[[{{M}^{2}}L{{T}^{-2}}\,{{A}^{-1}}]\]     

    C)        \[\left[ M{{L}^{-2}}{{A}^{-1}} \right]\]   

    D)        none of these

    Correct Answer: C

    Solution :

    \[\vec{F}=q\vec{v}\times \vec{B}\] or            \[F=q\,v\,B\,\sin \theta \] \[\therefore \]  \[[B]=\left[ \frac{F}{qv} \right]=\frac{[ML{{T}^{-2}}]}{[AT][L{{T}^{-1}}]}=[M{{T}^{-2}}{{A}^{-1}}]\]


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