A) \[N{{a}_{2}}S\]
B) \[AlC{{l}_{3}}\]
C) \[NaH\]
D) \[MgC{{l}_{2}}\]
Correct Answer: B
Solution :
We know that \[\text{A}{{\text{l}}^{\text{3+}}}\]cation is smaller than \[\text{N}{{\text{a}}^{\text{+}}}\] (because) of greater nuclear charge). According to Fajans rule, small cation polarize anion upto greater extent. Hence, \[\text{A}{{\text{l}}^{\text{3+}}}\] polarise \[\text{C}{{\text{l}}^{-}}\]ions upto greater extent, therefore, \[\text{AlC}{{\text{l}}_{\text{3}}}\]has covalent bond between Al and \[\text{Cl}-\]atoms.
You need to login to perform this action.
You will be redirected in
3 sec
