A) \[11\times {{10}^{3}}\,cal\]
B) \[22\times {{10}^{3}}cal\]
C) \[33\times {{10}^{3}}cal\]
D) \[25\times {{10}^{3}}cal\]
Correct Answer: B
Solution :
\[H=\frac{I_{v}^{2}RT}{J}cal\] \[=\frac{{{(\sqrt{2})}^{2}}\times 110\times 7\times 60}{4.2}\] \[\left( \because \,{{I}_{rms}}=\frac{{{I}_{0}}}{\sqrt{2}}=\frac{220/110}{\sqrt{2}}=\sqrt{2} \right)\] \[=22\times {{10}^{3}}\,cal\]
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