A) \[\frac{1}{4}m{{\omega }^{2}}{{A}^{2}}\]
B) \[\frac{1}{2}m{{\omega }^{2}}{{A}^{2}}\]
C) \[m{{\omega }^{2}}{{A}^{2}}\]
D) 0
Correct Answer: A
Solution :
Average energy \[=\,\,\frac{\int_{0}^{T}{Udt}}{\int_{0}^{T}{dt}}=\frac{1}{T}\int_{0}^{T}{Udt}\] \[=\frac{1}{2T}\int_{0}^{T}{m{{\omega }^{2}}{{A}^{2}}{{\cos }^{2}}(\omega t+o|)}\,dt\]\[=\frac{1}{4}m{{\omega }^{2}}{{A}^{2}}\]
You need to login to perform this action.
You will be redirected in
3 sec
