VMMC VMMC Medical Solved Paper-2004

  • question_answer
    A thin circular ring of mass M and radius r is rotating about its axis with a constant angular velocity\[\omega \]. If two objects of mass m are attached gently to opposite ends of a diameter of ring, ring will now rotate with an angular velocity given by

    A) \[\frac{2\omega M}{(M-2m)}\]

    B)        \[\frac{(M-2m)}{M}\]   

    C)        \[\frac{\omega M}{(M+2m)}\] 

    D)        \[\frac{2\omega M}{(M-2m)}\]

    Correct Answer: C

    Solution :

    From the law of conservation of momentum \[{{I}_{1}}{{\omega }_{1}}={{I}_{2}}{{\omega }_{2}}\] \[M{{r}^{2}}\omega =(M+2m){{r}^{2}}\omega \] Thus,                     \[\omega =\frac{\omega M}{M+2m}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner