A) \[n-\]propyl alcohol
B) isopropyl alcohol
C) ethyl alcohol
D) butyl alcohol
Correct Answer: B
Solution :
\[\text{C}{{\text{H}}_{2}}=CH-C{{H}_{3}}+{{H}_{2}}O\xrightarrow{{{H}_{2}}S{{O}_{4}}}\] \[\underset{\text{Isopropyl}\,\text{alcohol}}{\mathop{\underset{C{{H}_{2}}-CH-C{{H}_{3}}}{\overset{OH}{\mathop{|}}}\,}}\,\] Thus in this reaction isopropyl alcohol is formed.
You need to login to perform this action.
You will be redirected in
3 sec
