A) \[\text{C}{{\text{l}}_{\text{2}}}\]
B) \[\text{OCl}\]
C) \[\text{O}{{\text{F}}_{2}}\]
D) \[{{\text{O}}_{\text{2}}}{{\text{F}}_{\text{2}}}\]
Correct Answer: B
Solution :
We know that \[{{O}_{3}}+CC{{l}_{2}}{{F}_{2}}\xrightarrow{{}}2OCl+{{F}_{2}}O.\]Thus in this reaction \[\text{OCl}\] is produced
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