A) \[C{{H}_{3}}C{{H}_{2}}CHO\]
B) \[C{{H}_{3}}CHO\]
C) \[HCHO\]
D) \[C{{H}_{3}}COC{{H}_{3}}\]
Correct Answer: B
Solution :
We know that \[\underset{\text{Acetaldehyde}}{\mathop{C{{H}_{3}}-\overset{H}{\mathop{\overset{|}{\mathop{C}}\,}}\,=O}}\,\xrightarrow{{}}\underset{\text{Cyanohydrin}}{\mathop{C{{H}_{3}}-\underset{CN}{\overset{H}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,-OH}}\,\] \[\xrightarrow{{}}\underset{\text{Lactic}\,\text{acid}}{\mathop{C{{H}_{3}}-\underset{COOH}{\overset{H}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,-OH}}\,\] Thus lactic acid is formed.
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