A) \[F{{e}_{3}}{{O}_{4}}\]
B) \[A{{l}_{2}}{{O}_{3}}\]
C) \[Ca{{C}_{2}}\]
D) \[A{{l}_{4}}{{C}_{3}}\]
Correct Answer: D
Solution :
We know that \[A{{l}_{4}}{{C}_{3}}+12{{H}_{2}}O\xrightarrow{{}}4\,Al{{(OH)}_{3}}+3C{{H}_{4}}\] Thus in this reaction methane \[(C{{H}_{4}})\] is produced.
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