A) 1.4 V
B) 2.8 eV
C) 4.2 eV
D) 0.7 V
Correct Answer: A
Solution :
The relation between stopping potential and work function is given by \[e{{V}_{s}}=E-W=2-0.6=1.4\,eV\] Hence, \[{{V}_{s}}=\frac{1.4\times 1.6\times {{10}^{-19}}}{1.6\times {{10}^{-19}}}\] \[=1.4\,\text{volt}\]
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