2. Solved Papers
  3. VMMC

VMMC VMMC Medical Solved Paper-2003

  • question_answer
    The angle of prism is \[60{}^\circ \] and angle of deviation is \[30{}^\circ \]. In the position of minimum deviation, the angle of incidence i and the angle of emergence e are:

    A) \[i=45{}^\circ ,\text{ }e=50{}^\circ \]      

    B)        \[i=30{}^\circ ,\text{ }e=45{}^\circ \]

    C)        \[i=45{}^\circ ,\text{ }e=45{}^\circ \]

    D)        \[i=30{}^\circ ,\text{ }e=30{}^\circ \]

    Correct Answer: C

    Solution :

    In the position of minimum deviation, the angle of incidence is given by \[=\frac{A+\delta m}{2}\] \[=\frac{60+30}{2}={{45}^{o}}\] and angle of emergence = angle of incidence \[={{45}^{o}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner