A) \[\lambda =\frac{h}{m\upsilon }\]
B) \[\lambda =\frac{m\upsilon }{h}\]
C) \[\lambda =\frac{mh}{\upsilon }\]
D) \[\lambda =\frac{h\upsilon }{m}\]
Correct Answer: A
Solution :
de-Broglie gave an equation to give relation between wavelength of wave associated with a particle with momentum \[(m\upsilon ).\]This equation is: \[\lambda =\frac{h}{m\upsilon }\] where, \[h=\]Plancks constant \[(6.626\times {{10}^{-34}}\,Js)\]
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