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VMMC VMMC Medical Solved Paper-2003

  • question_answer
    For the reaction, \[CO(g)+{{H}_{2}}O(g)\rightleftharpoons C{{O}_{2}}(g)+{{H}_{2}}(g)\] at \[\text{200}{{\,}^{\text{o}}}\text{C,}\,\,{{P}_{C{{O}_{2}}}}=0.2\,\text{atm}\text{.,}\,\,{{\text{P}}_{{{\text{H}}_{2}}}}=0.1\,\text{atm}\text{.,}\] \[{{\text{P}}_{\text{CO}}}\text{=}\,\text{2}\,\text{atm}\text{.,}\]and \[{{\text{P}}_{{{\text{H}}_{2}}O}}=0.01\,\text{atm}\text{.}\]The value of \[{{K}_{c}}\] will be:              

    A)  1.2                                        

    B)  1.0

    C)  0.028                   

    D)         2.42

    Correct Answer: A

    Solution :

    \[CO(g)+{{H}_{2}}O(g)\rightleftharpoons C{{O}_{2}}(g)+{{H}_{2}}(g)\] For this reaction, \[\Delta {{n}_{g}}=2-2=0\] \[\therefore \]  \[{{K}_{c}}={{K}_{p}}\]   \[({{K}_{c}}={{K}_{p}}{{(RT)}^{\Delta {{n}_{g}}}})\]                 \[=\frac{{{P}_{C{{O}_{2}}}}.{{P}_{{{H}_{2}}}}}{{{P}_{H{{O}_{2}}}}.{{P}_{CO}}}\]                 \[=\frac{0.2\times 0.1}{0.01\times 2}\]                 \[=1.0\]


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