question_answer

The product \[\Upsilon \] in the reaction, is: \[C{{H}_{3}}-C\equiv CH\xrightarrow{2HBr}X\xrightarrow{aq.NaOH}\Upsilon \]

A)  \[C{{H}_{3}}CHO\]         

B)  \[~C{{H}_{2}}C{{H}_{2}}COOH\]

C)         \[C{{H}_{3}}C{{H}_{2}}CHO\]

D)         \[C{{H}_{3}}COC{{H}_{3}}\]

Correct Answer: D

Solution :

The  reaction  occurs  according  to Markownikoffs rule: \[C{{H}_{3}}-C\equiv CH\xrightarrow{2HBr}\underset{\text{aq}\text{.NaOH}}{\mathop{C{{H}_{3}}-\underset{Br}{\overset{Br}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,-C{{H}_{3}}}}\,\]