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VMMC VMMC Medical Solved Paper-2003

  • question_answer
    Ethanamide on treatment with \[\text{B}{{\text{r}}_{\text{2}}}\text{/NaOH,}\] gives:

    A)  ethanamine   

    B)         ethyl alcohol

    C)         methanamine  

    D)         bromoform

    Correct Answer: C

    Solution :

    Amides, on reaction with \[\text{B}{{\text{r}}_{\text{2}}}\text{/NaOH,}\]gives one carbon less amines. This is Hofmann-bromamide reaction. \[C{{H}_{3}}CON{{H}_{2}}\xrightarrow{B{{r}_{2}}/NaOH}C{{H}_{3}}N{{H}_{2}}\]


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