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VMMC VMMC Medical Solved Paper-2003

  • question_answer
    In the case of a radio isotope, the value of \[{{\text{t}}_{1/2}}\] and \[\lambda \]are identical in magnitude. The value is:

    A)  \[\frac{1}{0.693}\]         

    B)         \[{{(0.693)}^{1/2}}\]     

    C)  \[\frac{0.693}{2}\]         

    D)         \[0.693\]

    Correct Answer: B

    Solution :

    We know that, \[{{t}_{1/2}}=\frac{0.693}{\lambda }\] or            \[{{({{t}_{1/2}})}^{2}}=0.693\]                    \[(\because \,{{t}_{1/2}}=\lambda )\] or            \[{{t}_{1/2}}=\lambda ={{(0.693)}^{1/2}}\]


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