A) \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}OH\]
B) \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}CHO\]
C) \[C{{H}_{3}}CH=CHC{{H}_{2}}OH\]
D) \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}OH\]
Correct Answer: C
Solution :
\[\text{LiAl}{{\text{H}}_{\text{4}}}\]reduces only carbonyl group prior to double bond. Hence, crotonaldehyde give crotonyl alcohol on reduction. \[\text{C}{{\text{H}}_{3}}CH=CH.CHO\xrightarrow{\text{LiAl}{{\text{H}}_{\text{4}}}}\] \[C{{H}_{3}}CH=CH.C{{H}_{2}}OH\]
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