A) \[9.0\times {{10}^{13}}J\]
B) \[7.0\,\times {{10}^{13}}J\]
C) \[4.0\times {{10}^{13}}J\]
D) \[5.3\times {{10}^{13}}J\]
Correct Answer: A
Solution :
Mass defect in 1 kg substance \[\Delta m=0.1%\,\]of 1kg \[=\frac{0.1}{100}\times 1=0.001\,kg\] From Einsteins mass-energy equivalence relation, energy released is \[\Delta E=(\Delta m){{c}^{2}}\] \[=0.001kg\times (3\times {{10}^{8}}m/se{{c}^{2}})\] \[=9.0\times {{10}^{13}}\,J\]
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