A) \[\text{C}{{\text{a}}^{2+}}\]
B) \[F{{e}^{2+}}\]
C) \[N{{i}^{2+}}\]
D) \[M{{n}^{2+}}\]
Correct Answer: D
Solution :
The electronic configuration of these ions are: \[C{{a}^{2+}}=1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},2{{s}^{2}}3{{p}^{6}}\] \[(n=0)\] \[F{{e}^{2+}}=1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{6}}3{{d}^{6}}\] \[(n=4)\] \[N{{i}^{2+}}=1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{6}}3{{d}^{8}}\] \[(n=2)\] \[M{{n}^{2+}}=1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{6}}3{{d}^{5}}\] \[(n=5)\] Hence, \[\text{M}{{\text{n}}^{\text{2+}}}\]has maximum number of unpaired electrons.
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