A) \[\text{0}\text{.5}\,\text{M}\,{{\text{H}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}\]
B) \[\text{1}\text{.2}\,\text{N}\,{{\text{H}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}\]
C) \[\text{48}\,\text{g/l}\text{.}\,{{\text{H}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}\]
D) 5% \[{{\text{H}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}\]by weight
Correct Answer: C
Solution :
\[\text{48}\,\text{g/1}\,{{\text{H}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}\]is the most dilute. For it, normality \[\text{(N)}\,\text{=}\,\frac{S}{E}=\frac{48}{49}=0.98\,N\] While 5% \[{{H}_{2}}S{{O}_{2}}=\frac{50\,g}{1}{{H}_{2}}S{{O}_{4}}\] \[=1.02\,N{{H}_{2}}S{{O}_{4}}\] and, \[0.5\,M{{H}_{2}}S{{O}_{4}}=1.0\,N{{H}_{2}}S{{O}_{4}}\]
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