A) 5\[\mu \] sec
B) 10\[\mu \] sec
C) 25\[\mu \] sec
D) 50 \[\mu \] sec
Correct Answer: B
Solution :
Time taken by proton in 1 revolution \[=\frac{25}{5}=5\,\mu \,\sec \] Now, we know that \[T=\frac{2\pi m}{Bq}\] \[\frac{{{T}_{1}}}{{{T}_{2}}}=\frac{{{m}_{1}}}{{{q}_{1}}}\times \frac{{{q}_{2}}}{{{m}_{2}}}\] \[{{T}_{2}}=\frac{{{T}_{1}}\times {{q}_{1}}\times {{m}_{2}}}{{{m}_{1}}\times q\,}\] \[=\frac{5\times q\times 4{{m}_{1}}}{{{m}_{1}}\times 2q}\] \[\left[ \begin{align} & \because \,{{m}_{2}}=4{{m}_{1}} \\ & \text{and}\,{{q}_{2}}=2q \\ \end{align} \right]\] \[=10\,\mu \sec \]
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