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VMMC VMMC Medical Solved Paper-2003

  • question_answer
    A bullet is fired from gun. The force on the bullet is given by \[F=600\,-2\times {{10}^{5}}\,t,\] where F is in neutron and t in second. The force on the bullet becomes zero as soon as it leaves the barrel. What is the average impulse imparted to the bullet?

    A)  1.8 N    

    B)                         zero                     

    C)  9 N                       

    D)         0.9N

    Correct Answer: B

    Solution :

    The force is given by \[F=600-2\times {{10}^{5}}t=0\] So, time for which force acts is \[t=\frac{600}{2\times {{10}^{5}}}\] \[=3\times {{10}^{-3}}\sec \] \[\therefore \] Average impulse \[\text{= force  }\!\!\times\!\!\text{  time}\] \[=(600-2\times {{10}^{5}}\times 3\times {{10}^{-3}})\] \[=0\]


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