A) cupra ammonium hydroxide
B) cupra ammonium sulphate
C) Both (a) and (b)
D) none of these
Correct Answer: B
Solution :
When \[\text{CuS}{{\text{O}}_{\text{4}}}\]reacts with \[\text{N}{{\text{H}}_{\text{4}}}\text{OH,}\]deep blue colour is formed due to the formation of cupra ammonium sulphate. \[\underset{\text{Copper}\,\text{sulphate}}{\mathop{\text{CuS}{{\text{O}}_{4}}}}\,+\underset{\left( \begin{smallmatrix} \text{ammonium} \\ \text{hydroxide} \end{smallmatrix} \right)}{\mathop{N{{H}_{4}}OH}}\,\xrightarrow{{}}\underset{\begin{smallmatrix} \text{Cupra}\,\text{ammonium} \\ \text{sulphate} \end{smallmatrix}}{\mathop{[Cu{{(N{{H}_{3}})}_{4}}]S{{O}_{4}}}}\,\]
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