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VMMC VMMC Medical Solved Paper-2002

  • question_answer
    The E.A.N. of Ni in \[\text{Ni(CO}{{\text{)}}_{\text{4}}}\] is:

    A)  36                         

    B)  34                         

    C)  32                         

    D)         30

    Correct Answer: A

    Solution :

                    In \[Ni{{(CO)}_{4}}\][CO is a neutral ligand] E. A.N. of Ni = Atomic weight \[-\text{oxidation}\,\text{state}+2\times \text{ligands}\] \[=28-0+2\times 4=36\]


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