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VMMC VMMC Medical Solved Paper-2002

  • question_answer
    Oxidation number of aluminium in \[\text{N}{{\text{a}}_{\text{3}}}\text{Al}{{\text{F}}_{\text{6}}}\] is:

    A)  + 3                        

    B)         + 2        

    C)  - 2                         

    D)         + 1

    Correct Answer: A

    Solution :

    In \[\text{N}{{\text{a}}_{\text{3}}}\text{Al}{{\text{F}}_{\text{6}}}\] \[(+1\times 3)+x+(-1\times 6)=0\]                                 \[3+x-6=0\]                                 \[x=+3\] \[\therefore \] Oxidation number of Al is \[+3.\]


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