A) 33.15 N
B) 18.3 N
C) 198 N
D) 35 N
Correct Answer: A
Solution :
\[\text{Density}\,\text{=}\frac{\text{mass}}{\text{volume}}\] \[=\frac{1.21\,g}{1\,\text{ml}}=\frac{1.21\times 1000\,g}{1\,\text{litre}}\] \[=1210\,\,\text{g/litre}\] Equivalent weight of \[\text{HCl}\,\text{=}\,\text{36}\text{.5}\] \[\text{Normality}\,\text{=}\,\frac{}{\text{E}\text{.V}\,\text{(litre)}}.\] \[=\frac{1210}{36.5\times 1}=33.15\,N\]
You need to login to perform this action.
You will be redirected in
3 sec
