A) 22.4 litre
B) 10 litre
C) 2.24 litre
D) 15 litre
Correct Answer: C
Solution :
\[CaC{{O}_{3}}\xrightarrow{\Delta }CaO+C{{O}_{2}}\uparrow \] \[\left( \begin{align} & 40\,+12+16\times 3 \\ & =100 \\ \end{align} \right)\] \[\because \]At S.T.P 100 g\[\text{CaC}{{\text{O}}_{\text{3}}}\]on decomposition gives\[\text{C}{{\text{O}}_{2}}=22.4\,\text{litre}\] \[\therefore \]At S.T.P 10 g \[\text{CaC}{{\text{O}}_{\text{3}}}\]on decomposition gives \[C{{O}_{2}}=\frac{22.4}{100}\times 10\] \[=2.24\,\text{litre}\]
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