VMMC VMMC Medical Solved Paper-2002

  • question_answer
    The half life is 5 min. How much % of radioactive compound remains after 20 minutes?

    A)  6.25%                                  

    B)  93.75%

    C)         12.5%                  

    D)         87.5%

    Correct Answer: A

    Solution :

    \[T=n\times {{t}_{1/2}}\] \[20=n\times 5\] \[n=4\] \[\frac{N}{{{N}_{0}}}={{\left( \frac{1}{2} \right)}^{n}}\] \[\frac{N}{100}={{\left( \frac{1}{2} \right)}^{4}}\]or \[N=\frac{100}{16}=6.25%\]


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