A) \[N{{a}_{3}}Al{{F}_{6}}\]
B) \[CaC{{l}_{2}}.A{{l}_{2}}{{(S{{O}_{4}})}_{3}}\]
C) \[F{{e}_{4}}[Fe{{(CN)}_{6}}]\]
D) \[A{{l}_{2}}{{O}_{3}}.2{{H}_{2}}O\]
Correct Answer: A
Solution :
Cryolite \[(N{{a}_{3}}Al{{F}_{6}})\] is an ore of aluminium. In the Hall process cryolite is used with \[\text{A}{{\text{l}}_{\text{2}}}{{\text{O}}_{\text{3}}}\]because cryolite increase the electrical conductivity of cell as \[\text{A}{{\text{l}}_{\text{2}}}{{\text{O}}_{\text{3}}}\]is a poor conductor.
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