A) \[\sqrt{2}:2\]
B) 1: 4
C) 2 : 1
D) 1 : 2
Correct Answer: D
Solution :
From the formula of linear momentum \[p=\sqrt{2m{{E}_{k}}}\] \[\therefore\] \[\frac{{{p}_{p}}}{{{p}_{\alpha}}}=\frac{\sqrt{{{m}_{p}}}}{{{m}_{\alpha}}}=\frac{\sqrt{1}}{4}=\frac{1}{2}\] So, \[{{p}_{p}}:{{p}_{\alpha }}=1:2\]
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