A) \[\text{NaH}\]
B) \[\text{HCl}\]
C) \[\text{N}{{\text{H}}_{3}}\]
D) \[\text{Si}{{\text{H}}_{\text{4}}}\]
Correct Answer: A
Solution :
Sodium hydride \[(NaH)\] on ionization give \[\text{N}{{\text{a}}^{\text{+}}}\] and \[{{\text{H}}^{-}}.\] So it is an ionic hydride, while \[\text{HCl,N}{{\text{H}}_{\text{3}}}\] and \[\text{Si}{{\text{H}}_{4}}\] are covalent hydride.
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