A) 0.4\[\overset{0}{\mathop{A}}\,\]
B) 0.3\[\overset{0}{\mathop{A}}\,\]
C) 0.2 \[\overset{0}{\mathop{A}}\,\]
D) 0.1\[\overset{0}{\mathop{A}}\,\]
Correct Answer: D
Solution :
Here: potential difference \[V=120\,kV=120\times {{10}^{3}}V\] From the formula for minimum wavelength \[{{\lambda }_{\min }}=\frac{hc}{eV}=\frac{6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}{(1.6\times {{10}^{-19}})\times 120\times {{10}^{3}}}=0.1\,\overset{\text{o}}{\mathop{\text{A}}}\,\]
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