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VMMC VMMC Medical Solved Paper-2002

  • question_answer
    To find the radius of a circular path of an electron, when subjected to a perpendicular magnetic field is:

    A) \[\frac{m\upsilon }{Be}\]                            

    B)        \[\frac{me}{B}\]                              

    C) \[\frac{mE}{B}\]                              

    D)         \[\frac{Be}{m\upsilon }\]

    Correct Answer: A

    Solution :

    Centripetel force \[=\frac{m{{\upsilon }^{2}}}{r}\]and force on a moving electron in the magnetic field \[=Be\upsilon \] Hence,                  \[\frac{m{{\upsilon }^{2}}}{r}=Be\,\upsilon \] or                            \[r=\frac{m\upsilon }{Be}\]  (Here, r is the radius of circular path)


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