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VMMC VMMC Medical Solved Paper-2002

  • question_answer
    In a coil of self-inductance 5 henry, the rate of change of current is 2 amp per second. The emf induced in the coil is:

    A)  -5V                       

    B)         5                            

    C)         -10 V    

    D)                         10 V

    Correct Answer: C

    Solution :

    Here: inductance of the coil L = 5 H Rate of change of current\[\frac{di}{dt}=2A/\sec \] The induced emf is given by \[=-L\frac{di}{dt}=-5\times 2=-10\,V\]  


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