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VMMC VMMC Medical Solved Paper-2002

  • question_answer
    In Youngs double slit experiment the intencity at centre of screen is 1. If one of the slit is closed, the intensity at centre now will be:

    A) \[\frac{I}{2}\]                    

    B)        \[I\]                      

    C) \[\frac{I}{4}\]                    

    D)        \[\frac{I}{3}\]    

    Correct Answer: C

    Solution :

    The intensity at the centre is constructive i.e.,        \[I={{({{A}_{1}}+{{A}_{2}})}^{2}}.\] In Youngs double slit experiment \[{{A}_{1}}={{A}_{2}}=A=\]amplitude of waves passing through the identical slit So,           \[I=4{{A}^{2}}\]                                               ?(1) If one slit is closed, the remaining intensity \[I={{A}^{2}}\]                                                   ?(2) Hence, from Eqs. (1) and (2), we obtain \[I=I/4\]


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