A) 720 m/s
B) 480 m/s
C) 240 m/s
D) 180 m/s
Correct Answer: B
Solution :
Here: path difference \[\Delta x=1\,m\] Phase difference \[={{90}^{o}}=0.5\pi \] Frequency \[n=120\,Hz\] \[\therefore \] Phase difference\[\text{o }\!\!|\!\!\text{ =}\frac{2\pi }{\lambda }\times \Delta x\] or \[\lambda =\frac{2\pi \times \Delta x}{\text{o }\!\!|\!\!\text{ }}=\frac{2\pi \times 1}{0.5\pi }=4m\] Hence, wave velocity \[\upsilon =n\lambda =120\times 4=480\,m/s\]
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