A) W
B) 4W
C) 3W
D) 2W
Correct Answer: B
Solution :
From the formula, work done or energy is \[W=\frac{1}{2}C{{V}^{2}}\] or \[W\propto {{V}^{2}}\] Given, \[{{V}_{2}}=60-30=30V\] \[{{V}_{1}}=30-15=15V,{{W}_{1}}=W\] Hence, \[\frac{{{W}_{1}}}{{{W}_{2}}}={{\left( \frac{{{V}_{1}}}{{{V}_{2}}} \right)}^{2}}\] \[\frac{{{W}_{2}}}{{{W}_{1}}}={{\left( \frac{{{V}_{2}}}{{{V}_{1}}} \right)}^{2}}\] \[{{W}_{2}}={{\left( \frac{{{V}_{2}}}{{{V}_{1}}} \right)}^{2}}\times W={{\left( \frac{30}{15} \right)}^{2}}\times W=4\,W\]
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