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VMMC VMMC Medical Solved Paper-2002

  • question_answer
    A particle of mass 4 kg is acted upon by steady force of 4 N. Distance travelled by the particle in 4 sec is:

    A)  16 m                                    

    B)  2 m                       

    C)         8 m                       

    D)         4 m

    Correct Answer: C

    Solution :

    Using the formula \[F=ma\] or \[a=\frac{F}{m}\] or            \[a=\frac{4}{4}=1\,\,m/{{s}^{2}}\] Again from the equation of motion \[s=ut+\frac{1}{2}a{{t}^{2}}\] (Here, \[u=0\]and\[t=4\,\sec \])                 or            \[s=0+\frac{1}{2}\times 1\times {{(4)}^{2}}\]                 So,          \[s=8\,m\]


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