VMMC VMMC Medical Solved Paper-2002

  • question_answer
    If range and height of a projectile are equal, then angle of projection with the horizontal is:

    A) \[60{}^\circ \]   

    B)                         \[{{\tan }^{-1}}\,(4)\]

    C) \[30{}^\circ \]                   

    D)        \[45{}^\circ \]

    Correct Answer: B

    Solution :

    Using the formula for  rang \[R=\frac{{{u}^{2}}\sin (2\theta )}{g}\]                                   ?(1) And also from the formula for height \[H=\frac{{{u}^{2}}{{\sin }^{2}}\theta }{2g}\]                                       ?(2) According to the condition of question \[R=H\]                 or            \[\frac{{{u}^{2}}\sin 2\theta }{g}=\frac{{{u}^{2}}{{\sin }^{2}}\theta }{2g}\] \[\frac{2\sin \theta \cos \theta }{g}=\frac{{{\sin }^{2}}\theta }{2}\]or \[\tan \theta =4\] So,          \[\theta ={{\tan }^{-1}}(4)\]


You need to login to perform this action.
You will be redirected in 3 sec spinner