VMMC VMMC Medical Solved Paper-2002

  • question_answer
    If a source is moving away from a stationary observer with velocity of light. The frequency observed will be:

    A)  one-third                           

    B)  doubled             

    C)         halved

    D)                         unchanged

    Correct Answer: D

    Solution :

    The apparent frequency heard. When the source is moving away from the observer is: \[{{n}_{0}}=\frac{\upsilon }{\upsilon +{{\upsilon }_{s}}}{{n}_{s}}=\frac{\upsilon }{\upsilon +c}{{n}_{s}}\approx \]very very less = negligible (since \[\upsilon n,<<c\])


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