A) \[{{\tan }^{-1}}\left( 1 \right)\]
B) \[{{\sin }^{-1}}\left( \frac{1}{2} \right)\]
C) \[{{\sec }^{-1}}\left( 1 \right)\]
D) \[{{\tan }^{-1}}\left( \frac{1}{\sqrt{3}} \right)\]
Correct Answer: C
Solution :
\[\therefore \] \[\therefore \] \[56u=\frac{56}{14}Natom=4Natom\] \[\begin{align} & CaC{{O}_{3}}\xrightarrow{Heat}CaO+C{{O}_{2}}\uparrow \\ & \text{XColourless} \\ & \text{gas} \\ \end{align}\] That means, \[\theta ={{0}^{o}}\]\[\theta =2\pi \] \[\because \]\[\sec 2\pi =1\] \[\therefore \]\[\sec 2\pi =1\] \[\therefore \]\[2\pi ={{\sec }^{-1}}(1)\] \[\Rightarrow \]\[\theta ={{\sec }^{-1}}(1)\]
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